Showing posts with label Unit 11 : Thermal Properties of Matter. Show all posts
Showing posts with label Unit 11 : Thermal Properties of Matter. Show all posts

Sunday, November 21, 2010

Latent Heat

Latent Heat


Latent Heat (enthalpy) is the "hidden" heat when a substance absorbs or releases heat without producing a change in the temperature of the substance, eg, during a change of state.

Latent Heat of Fusion(Lf)


Latent Heat (enthalpy) of Fusion is the heat absorbed per mole when a substance changes state from solid to liquid at constant temperature (melting point).

The unit for Lf is Joule(J).


Specific Latent Heat of Fusion(l)

The specific latent heat is the amount of energy required to convert 1 kg (or 1 lb) of a substance from solid to liquid (or vice-versa) without a change in the temperature of the surroundings – all absorbed energy goes into the phase change.

Equation:

Q
= m
l

where:
Q is the amount of energy released or absorbed during the change of phase of the substance (in kJ or in BTU),
m is the mass of the substance (in kg or in lb), and
L is the specific latent heat for a particular substance (kJ/kg or in BTU/lb); substituted as Lf to represent as the specific latent heat of fusion


Latent Heat of Vapourization(Lv)

Latent Heat (enthalpy) of Vaporization (vaporisation) is the heat absorbed per mole when a substance changes state from liquid to gas at constant temperature (boiling point).

The unit for Lv is Joule(J).


Specific Latent Heat of Vapouriation(l)

The amount of energy required to convert 1 kg (or 1 lb) of a substance from liquid to gas (or vice-versa) without a change in the external temperature is known as the specific latent heat of vaporization for that substance.

Equation:

Q = mL



where:

Q is the amount of energy released or absorbed during the change of phase of the substance (in kJ or in BTU),
m is the mass of the substance (in kg or in lb), and
L is the specific latent heat for a particular substance (kJ/Kg or in BTU/lb); substituted as Lv as specific latent heat of vaporization.


Thermal Properties - States of Matter

Phase Transition of Water

Melting and Solidification



This graph shows the phase diagram of water.

At the beginning we have ice at -20 ºC. Ice gain heat in the interval of points A and B, and its temperature becomes 0 ºC that is the melting point of it. We have only ice in the 1st region.

As you can see between the points B and C, temperature of the mass does not change, because its state is changing in this interval. Gained heat is absorbed and spent on breaking the bonds of molecules. 2nd region includes both water and ice. .

After melting process completed, in the 3rd region there is only water and temperature of water starts to increase. When the temperature of the water becomes 100 ºC, it starts to boil and evaporation of it speeds up.

In region 4 our mass exists in two state, water and steam. After completion of evaporation, all water converted to the steam and in region 5 we have only vapor of water.

The graph given below shows the relation of temperature vs. heat of water vapor that lost heat.



This graph shows the condensation of water vapor which lost heat.

As it seen from the graph, steam lost heat and its temperature decreases at 100 ºC, at this temperature it condensate and becomes water, after heat lost it reaches at temperature 0 ºC and starts to freeze. Finally, if it continues to lost heat, their temperature also continues to decrease.

Evaporation




Evaporation is a type of vaporization of a liquid, that occurs only on the surface of a liquid.

Evaporation is a type of phase transition; it is the process by which molecules in a liquid state (e.g. water) spontaneously become gaseous (e.g. water vapor). Generally, evaporation can be seen by the gradual disappearance of a liquid from a substance when exposed to a significant volume of gas. Vaporization and evaporation however, are not entirely the same processes.

Evaporation requires thermal energy from the surroundings.Thermal energy from our bodies helps the water on our skin to evaporate taking away thermal energy from the surface of your skin helping us cool down.

Evaporation

1.Occurs at any temperature

2.Slow Process

3.Takes place only at the liquid surface

4.No bubbles are formed in the liquid

5.Temperature may change

6.Thermal energy is supplied by the surroundings


Boiling

1.Occurs at fixed temperature

2.Quick Process

3.Takes place throughout the liquid

4.Bubbles are formed in the liquid

5.Temperature remains constant

6.Thermal energy is supplied by an energy source



How does evaporation take place?

We know that the molecules are never at rest. They can have slight translational and vibrational motions about their mean positions.

They thus posses some amount of kinetic energy. Sometimes the molecules collide with each other and exchange their kinetic energies. Thus at any given time, the kinetic energy of a few molecules may become quite large and they can escape from the surface. The probability of escape from the surface is larger for molecule 1, as its cohesive force holding it back to the liquid is less than that experienced by molecule 2. This is how evaporation takes place.




Factors affecting Rate of Evaporation

Temperature

The rate of evaporation increases as the temperature of a liquid is increased, as it is an endothermic process. For example, a glass of hot water evaporates more rapidly than a glass of cold water.

Surface area

The larger the exposed surface area of the liquid the greater is the number of molecules escaping from its surface.

Humidity of Surrounding Air

If the air already has a high concentration of the substance evaporating, then the given substance will evaporate more slowly.

If the air is already saturated with other substances, it can have a lower capacity for the substance evaporating.

Flow rate of air

This is in part related to the concentration points above. If fresh air is moving over the substance all the time, then the concentration of the substance in the air is less likely to go up with time, thus encouraging faster evaporation. This is the result of the boundary layer at the evaporation surface decreasing with flow velocity, decreasing the diffusion distance in the stagnant layer.

Pressure

Evaporation happens faster if there is less exertion on the surface keeping the molecules from launching themselves.

Strength of intermolecular forces

The ease of evaporation of a liquid is related to the strength of the attractive forces between the molecules in the liquid. In polar liquids cohesive forces are strong while in non-polar liquids the cohesive forces are very weak and the molecules escape easily. For example, ether evaporates more rapidly than ethyl alcohol while ethyl alcohol evaporates quicker than water.

Presence of impurities

Impurities affect the vapour pressure of a liquid appreciably. The non-volatile impurities lower the vapour pressure of a liquid. If the liquid contains impurities, it will have a lower capacity for evaporation.

Saturday, November 20, 2010

Worked Examples on Heat Capacity and Specific Heat Capacity

Examples

  1. Calculate the amount of heat needed to increase the temperature of 250g of water from 20oC to 56oC.

    q = m x Cg x (Tf - Ti)
    m = 250g
    Cg = 4.18 J oC-1 g-1 (from table above)
    Tf = 56oC
    Ti = 20oC

    q = 250 x 4.18 x (56 - 20)
    q = 250 x 4.18 x 36
    q = 37 620 J = 38 kJ

  2. Calculate the specific heat capacity of copper given that 204.75 J of energy raises the temperature of 15g of copper from 25o to 60o.

    q = m x Cg x (Tf - Ti)
    q = 204.75 J
    m = 15g
    Ti = 25oC
    Tf = 60oC

    204.75 = 15 x Cg x (60 - 25)
    204.75 = 15 x Cg x 35
    204.75 = 525 x Cg
    Cg = 204.75 ÷ 204.75 = 0.39 JoC-1 g-1

  3. 216 J of energy is required to raise the temperature of aluminium from 15o to 35oC. Calculate the mass of aluminium.
    (Specific Heat Capacity of aluminium is 0.90 JoC-1g-1).

    q = m x Cg x (Tf - Ti)
    q = 216 J
    Cg = 0.90 JoC-1g-1
    Ti = 15oC
    Tf = 35oC

    216 = m x 0.90 x (35 - 15)
    216 = m x 0.90 x 20
    216 = m x 18
    m = 216 ÷ 18 = 12g

  4. The initial temperature of 150g of ethanol was 22oC. What will be the final temperature of the ethanol if 3240 J was needed to raise the temperature of the ethanol?
    (Specific heat capacity of ethanol is 2.44 JoC-1g-1).

    q = m x Cg x (Tf - Ti)
    q = 3240 J
    m = 150g
    Cg = 2.44 JoC-1g-1
    Ti = 22oC

    3240 = 150 x 2.44 x (Tf - 22)
    3240 = 366 (Tf - 22)
    8.85 = Tf - 22
    Tf = 30.9oC

Thermal Properties of Matter


Heat Capacity


What is Internal Energy?

Internal energy is defined as the energy associated with the random, disordered motion of molecules. It is separated in scale from the macroscopic ordered energy associated with moving objects; it refers to the invisible microscopic energy on the atomic and molecular scale.

For example, a room temperature glass of water sitting on a table has no apparent energy, either potential or kinetic . But on the microscopic scale it is a seething mass of high speed molecules traveling at hundreds of meters per second. If the water were tossed across the room, this microscopic energy would not necessarily be changed when we superimpose an ordered large scale motion on the water as a whole.



If the temperature of a substance rises, it is due to an increase in the average kinetic energy of its particles only.

What is heat capacity?

Heat capacity (usually denoted by a capital C, often with subscripts) is the measurable physical quantity that characterizes the amount of heat required to raise a body's temperature by 1K or 1*C.

Amount of Thermal energy needed depends on Object's mass.

Equation for Heat Capacity:



where,
Q - thermal energy needed in Joules(J)
T - Temperature change in K or *C

The unit for Heat Capacity(C) is J/Kg

Specific Heat Capacity

Specific Heat Capacity (c) of a substance is the amount of heat required to raise the temperature of 1g of the substance by 1oC (or by 1 K).

The units of specific heat capacity are J oC-1 g-1 or J K-1 g-1

Equation for Specific Heat Capacity:





where,
Q= Heat supplied to substance,
m= Mass of the substance,
c= Specific heat capacity,
T= Temperature rise.